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50x^2=75
We move all terms to the left:
50x^2-(75)=0
a = 50; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·50·(-75)
Δ = 15000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15000}=\sqrt{2500*6}=\sqrt{2500}*\sqrt{6}=50\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{6}}{2*50}=\frac{0-50\sqrt{6}}{100} =-\frac{50\sqrt{6}}{100} =-\frac{\sqrt{6}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{6}}{2*50}=\frac{0+50\sqrt{6}}{100} =\frac{50\sqrt{6}}{100} =\frac{\sqrt{6}}{2} $
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